tolong bantu yang bisa ok
Jawab:
[tex]\sf \dfrac{(x-2)^2}{169} - \dfrac{(y-1)^2}{25} = 1 \to \dfrac{(x-p)^2}{a^2} - \dfrac{(y-q)^2}{b^2} = 1[/tex]
p= 2, q= 1
c² = a² + b² = 169 +25 = 194
c= √194
[answer.2.content]free fire game owner
Jawab:
[tex]\sf \dfrac{(x-2)^2}{169} - \dfrac{(y-1)^2}{25} = 1 \to \dfrac{(x-p)^2}{a^2} - \dfrac{(y-q)^2}{b^2} = 1[/tex]
p= 2, q= 1
c² = a² + b² = 169 +25 = 194
c= √194
[answer.2.content]