Diketahui p x (3√2-√6) = 12. nilai p yang memenuhi adalah
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Jawab:
Tanda titik "." dibawah artinya kali
p x (3√2 - √6) = 12
[tex]p= \frac{12}{3\sqrt{2}-\sqrt{6} }\\\\p= \frac{12(3\sqrt{2}+\sqrt{6})}{(3\sqrt{2}-\sqrt{6} )(3\sqrt{2}+\sqrt{6}) }\\\\p= \frac{12(3\sqrt{2}+\sqrt{6})}{9.2-6 }\\\\p=\frac{12(3\sqrt{2} +\sqrt{6} )}{12} \\\\p=3\sqrt{2} +\sqrt{6}[/tex]
Penjelasan:
a² - b² = (a + b)(a - b)
[tex](3\sqrt{2})^{2} -(\sqrt{6})^{2} =(3\sqrt{2}-\sqrt{6} )(3\sqrt{2}+\sqrt{6})\\\\(3.3.\sqrt{2}.\sqrt{2}) -(\sqrt{6}.\sqrt{6}) =(3\sqrt{2}.3\sqrt{2}+3\sqrt{2}.\sqrt{6} -\sqrt{6} .3\sqrt{2} -\sqrt{6}. \sqrt{6} )\\\\9.\sqrt{4} -\sqrt{36} =9\sqrt{4} -\sqrt{36} -------- > sama\\\\=9.2-6[/tex]
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